Given 2^m + 2^m = 2^n, express m in terms of n.

m = n-1

Step-by-step explanation:

2^m + 2^m = 2^n

Add on the left

2( 2^m) = 2 ^ n

2^1 ( 2^m) = 2^n

We know that a^b* a^c = a^ (b+c)

2^(1+m) =  2^n

The bases are the same so the exponents are the same

1+m = n

Solving for m

1+m-1 = n-1

m = n-1

true

step-by-step explanation: