If the dimensions of the box are L= 5cm W=2.5cm H= 2.5 cm, and a raisin is 0.6cm; How many raisins could fit inside of the box

52 raisins

Step-by-step explanation:

we have dimensions of the box

L = 5cm ; W = 2.5cm ; H = 2.5cm

V(raisin) = 0.6 cm³

V(box) = L×W×H

= 5cm×2.5cm×2.5cm

= 31.25 cm³

Vbox/Vraisin = 31.25cm³/0.6cm³ = 52.08(3) = 52 raisins

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

the first one

step-by-step explanation:

just id the test.