Chicken eggs can be categorized as large if they weigh at least 2 ounces. Clare weighs 48 large eggs and finds that they have a mean weight of 2.1 ounces and a mean absolute deviation of 0.08 ounces. Interpret 0.08 ounces in this situation.

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Step-by-step explanation:

Given the following :

Large eggs : ≥2 ounces

Mean of 48 large eggs = 2.1 ounces

Mean absolute deviation = 0.08 ounces

0.08 ounces here is the mean absolute deviation of the 48 large eggs weighed, meaning that:

The average of the sum of the absolute differences in each individual egg and the mean value of all eggs weighed is 0.08.

This means that the average difference, variability or deviation in the weight of large eggs weighed is 0.08 ounces around the mean value of all eggs weighed.

Mean Absolute Deviation (MAD) :

Σ|xi - mean| / n

xi = each individual value

n = number of values

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation: