A pool in the shape of a rectangular prism is 6 meters long and 3 meters wide. the water in the pool is 1 meter deep. a. the density of water is about 1 gram per cubic centimeter. find the number of kilograms of water in the pool. question 2
b. you add 6000 kilograms of water to the pool. what is the depth of the water in the pool? write your answer as a fraction. the water is about meters deep.

1). Mass of water present= 18000 kg

2).4/3 meters deep

Step-by-step explanation:

Area of the rectangle= 6*3= 18m²

Volume of water in the pool

= Deepness of water*area of rectangle

= 1*18

= 18 m³

density of water is about 1 gram per cubic centimeter

In kg per m³= 1000 kg/me

Mass of water present= density*volume

Mass of water present= 1000*18

Mass of water present= 18000 kg

2)6000 kilograms of water is added to 18000 of

Total mass present= 6000+18000

Total mass present=24000 kg

If density= 1000kg/m³

Volume present= mass/density

Volume present= 24000/1000

Volume present= 24 m³

Area of the rectangle= 18 m²

deepness of the pool= volume/area

deepness of the pool= 24/18

deepness of the pool= 4/3 meters deep

this answer is !

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,