Find the number of ways of arranging the letters of the word MOSHOESHOE, if the letter M must always begin a word

7560.

Step-by-step explanation:

There are 9 letters after the M consisting of  3 O's, 2 H's, 2 H's and 2 E's.

So the number of ways is   9! / (3!*2!*2!*2!)

= 362880 / (6*2*2*2)

= 362880 / 48

= 7560.

The number of ways the word MOSHOESHOE can be rearranged, if the letter M must always begin a word is 75,600 ways

Given:

MOSHOESHOE

n = total number of letters = 10

a = number of times O appears = 3

b = number of times S appears = 2

c = number of times E appears = 2

d = number of times H appears = 2

number of ways the word can be rearranged if M must always begin a word

= n! / (a! b! c! d!)

= 10! / (3!, 2!, 2!, 2!)

= (10 × 9 × 8 × 7 × 6 × 5 × 4× 3 × 2 × 1) / (3 × 2 × 1, 2 × 1, 2 × 1, 2 × 1)

= 3,628,800 / (6 × 2 × 2 × 2)

= 3,628,800 / 48

= 75,600 ways

Therefore, the number of ways the word can be rearranged if M must always begin a word is 75,600 ways

Read more:

link

d

step-by-step explanation: