The electrical resistance of a wire, R, varies directly as its length, L, and inversely as its cross sectional area, A. If the resistance of a wire is 0.08 ohm when the length is 100 ft and its cross-sectional area is 0.05 in^2 , what is the resistance of a wire whose length is 4000 ft with a cross-sectional area of 0.02in^2 ? a) Write the variation equation. (R=k(l/a) b) Determine the value of the quantity indicated. WILL MARK BRAINLIEST - 50PTS! NEED FAST - with work please so I understand how to do it, thank you:)

Step-by-step explanation:

(A)

Length of wire = 30.48 m

Area of cross section = 3.22 * 10 ^ -5 m^2

(B) length of wire = 1219.2 m

Area of cross section = 1.29 * 10^-5 m^2

Resistance = 8.45 * 10^-8 * 1219.2 / 1.29 * 10^-5 = 7.98 Ohms

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step-by-step explanation:

option b  

step-by-step explanation:

we know that

the distance from point n to lm in the figure is equal to the distance of the perpendicular line to lm that passes through the point n

so

the distance is equal to the segment no

> given problem

therefore

the distance from point n to lm is equal to