A plan for a baseball diamond is drawn in a coordinate plane. The baseball diamond is in the shape of a square with vertices at approximately 0, 04105401 (0-64 and 1-6401 One unit in the coordinate plane representa 1. What is th approximate area of the baseball diamond? Show your work.

The approximate area, of the baseball diamond is 8192 ft²

Step-by-step explanation:

The given coordinates of the baseball diamond are;

(0, 64), (64, 0), (0, -64), and (-64, 0)

The length of one unit of the coordinate plane = 1 foot

Therefore, we note that, there are two points with x-coordinate = 0 at which the y-coordinates = 64 and -64

Similarly here are two points with y-coordinate = 0 at which the x-coordinates = 64 and -64

The length of the segment are therefore the vertices of a square as we have;

A(0, 64), B(64, 0), C(0, -64), and D(-64, 0)

∠DBA = ∠DCA = tan⁻¹(64/64) = tan⁻¹(1) = 45°

∠DBA + ∠DCA = ∠ABC = 90°

The shape of the diamond is a square

The length, l of the side of the square is given by the relation;

When, (x₁, y₁) = (0, 64), (x₂, y₂) = (64, 0)

We have;

The

The area, A, of the baseball diamond is therefore;

A = Area of a square = (Length of the side of a square)² = (64·√2)² = 8192 ft²

The area, of the baseball diamond = 8192 ft².

x= 149. 24+7=31. 180-31=149

your welcome

answer: 1+1

step-by-step explanation: 1+1 is at least 2