If f and g are differentiable functions for all real values of x such that f(2) = 5, g(2) = 3, f '(2) = 1, g '(2) = -2, then find h '(2) if h(x) = f(x) g(x).

Step-by-step explanation:

So we have:

Differentiate. Use the product rule:

Substitute 2 for x:

We know that f'(2) is 1, f(2) is 5, g(2) is 3, and g'(2) is -2. Make the appropriate substitutions:

Simplify:

Subtract:

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation:

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.