The following list details the numbers of tickets sold for a talent show grade 9:22; grade 10:32; grade 11: 41; and grade 12:30. What are the domain and range of this relation?
A domain: (22, 32, 41, 30); range: {9, 10, 11, 12}
B. domain: {9, 22, 10, 32); range: {11, 41, 12, 30}
C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)
D
domain: {11, 41, 12, 30}; range: {9, 22, 10, 32)

C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)

Step-by-step explanation:

The data set is:

(9, 22)

(10,32)

(11, 41)

(12, 30).

In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).

Then the domain would be:

{9, 10, 11, 12}

and the range:

{22, 32, 41, 30}

The correct option is C

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.