Geometry PLEASE HELP will give le brainliest

From the given diagram, the measurement of ∠RQS is 106° and the measurement of ∠TQS is 74°

Step-by-step explanation:

For this problem, we are to find the measurements of ∠RQS and ∠TQS which makes up the straight line RQT. Straight lines have a measurement of 180°. So, since ∠RQS and ∠TQS make up ∠RQT, then we are goingt o set up an equation where we add ∠RQS and ∠TQS together and equal them to ∠RQT.

m∠RQS + m∠TQS = m∠RQT

Now, let's fill the information from the problem into our equation.

(11x + 7) + (8x + 2) = 180

Combine like terms on the left side of the equation.

19x + 9 = 180

Subtract 9 form both sides of the equation.

19x = 171

Divide by 19 on both sides of the equation.

x = 9

So, we know the value of x is 9. Now, let's plug in this value into each angle so we can see the measurements of each.

m∠RQS = 11(9) + 7 = 99 + 7 = 106°

m∠TQS = 8(9) + 2 = 72 + 2 = 74°

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.