Which of the following circumstances would likely make factoring the best method for solving a quadratic equation? A. The leading coefficient is zero

B. The difference of 2 perfect squares

C. A quadratic that is prime

D. The leading coefficient is not 1 and the constant is a large number

The correct option is;

B. The difference of 2 perfect squares

Step-by-step explanation:

Solving a quadratic equation using factoring involves finding the factors of the equation that would yield the result of the quadratic equation

In order to find the roots of the quadratic equation, then the result of the factoring must be equal to zero, in which case, the constant terms in the factors are the solutions of the quadratic equation in opposite sign.

For example, we have;

x² - 5² = 11

We subtract 11 from both sides to get;

x² - 5² - 11  = 11 - 11

x² - 36 = 0

x² - 6² = 0

(x - 6) × (x + 6) = 0

Therefore, x = 6 or -6 which are the opposite sign of the constant terms in the factor.

wfirfkfr/jjfi; jn; p/ojkfvlbvmkmgkgkkkgkkg

step-by-step explanation:

where's the diagram?

step-by-step explanation: