A random sample of 16 students selected from the student body of a large university had an average age of 25 years and a standard deviation of 2 years. We want to determine if the average age of all the students at the university is significantly more than 24. Assume the distribution of the population of ages is normal. The p-value is between

The P-value is between 2.5% and 5% from the t-table.

Step-by-step explanation:

We are given that a random sample of 16 students selected from the student body of a large university had an average age of 25 years and a standard deviation of 2 years.

Let = true average age of all the students at the university.

So, Null Hypothesis, : 24 years     {means that the average age of all the students at the university is less than or equal to 24}

Alternate Hypothesis, : > 24 years     {means that the average age of all the students at the university is significantly more than 24}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

                               T.S.  =    ~  

where, = sample average age = 25 years

             s = sample standard deviation = 2 years

             n = sample of students = 16

So, the test statistics =    ~    

                                     =  2  

The value of t-test statistics is 2.

Also, the P-value of test-statistics is given by;

            P-value = P( > 2) = 0.034 {from the t-table}

The P-value is between 2.5% and 5% from the t-table.

goog may have it for you

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!