Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 56.6 degrees. Low Temperature (◦F) 40−44 45−49 50−54 55−59 60−64 Frequency 2 7 9 5 2 The mean of the frequency distribution is nothing degrees.

Computed mean = 51.6

Actual mean > computed mean

Step-by-step explanation:

Low temp. - - Freq(f) - - midpoint(x) - - fx

40−44 - - - - - 2 - - - - - - - 42 - - - - - - 84

45−49 - - - - - 7 - - - - - - - 47 - - - - - - 329

50−54 - - - - - 9 - - - - - - - 52 - - - - - - 468

55−59 - - - - - 5 - - - - - - - 57 - - - - - - 285

60−64 - - - - - 2 - - - - - - - 62 - - - - - - 124

Mean (m) = Σ(fx) / Σ(f)

Σ(fx) = 84 + 329 + 468 + 285 + 124 = 1290

Σ(f) = 2 + 7 + 9 + 5 + 2 = 25

Mean (m) = 1290 / 25

Computed mean (m) = 51.6

Actual mean = 56.6

Actual mean > computed mean

56.6 > 51.6

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

u

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)