Mathematics, 29.08.2020 21:01 sheram2010

The amount y (in grams) of the radioactive isotope phosphorus-32 remaining after t
days is y=a(0.5)t/14
y
=
a
(
0.5
)
t
/
14
, where a
a
is the initial amount (in grams). What percent of the phosphorus-32 decays each day? Round your answer to the nearest hundredth of a percent.

Answers: 2

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The amount y (in grams) of the radioactive isotope phosphorus-32 remaining after t
days is y=...