Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50 +3.750 - 2071.50, where a is the number of adult tickets sold and b
is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students
attended, how may adult tickets were sold?
adult tickets
Intro
Done

168 adult tickets were sold

Step-by-step explanation:

$10. 50 per adults

$3. 75 per student

There are 82 students..

.. So...

$3. 75 × 82 = $307. 50

Overall the amount of money made was $2071.50

If you subtract $307.50 from $2071. 50 you will get $1,764

We now need to find out how many adults bought tickets by dividing $1, 764 by the price adults have to pay so..

Amount of adults who bought tickets are

= $1, 764 ÷ $10. 50

= 186 adults

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: