What is the area of the figure composed of a parallelogram, a square and a rectangle ?

Answer : The area of the figure composed of a parallelogram, a square and a rectangle is 126 in².

Step-by-step explanation :

Area of composed figure = Area of parallelogram + Area of square + Area of rectangle

First we have to calculate the area of parallelogram.

Area of parallelogram = Base × Height

Given:

Base = 10 in

Height = 3.5 in

Area of parallelogram = 10 in × 3.5 in

Area of parallelogram = 35 in²

Now we have to calculate the area of square.

Area of square = (Side)²

Given:

Side = 4 in

Area of square = (4 in)²

Area of square = 16 in²

Now we have to calculate the area of rectangle.

Area of rectangle = Length × Breadth

Given:

Length = 12.5 in

Breadth = 6 in

Area of rectangle = 12.5 in × 6 in

Area of rectangle = 75 in²

Now we have to calculate the composed figure.

Area of composed figure = Area of parallelogram + Area of square + Area of rectangle

Area of composed figure = 35 in² + 16 in² + 75 in²

Area of composed figure = 126 in²

Therefore, the area of the figure composed of a parallelogram, a square and a rectangle is 126 in².

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno

it is probably the graph on the bottom right.