At the north campus of a performing arts school, 20% of the students are music majors. At the south campus, 70% of the students are music majors. The campuses are merged into one east campus. If 30% of the 1000 students at the east campus are music majors, how many students did the north and south campuses have before the merger?

The north campus had while the south campus had .

Step-by-step explanation:

The question stated that there are students in the merged campus. That's the sum of the number of students in the north and the south campus before the merger.

Let denote the number of students in the north campus before the merger. The other students would all belong to the south campus before the merger.

Before the merger, of the students of the north campus are of music majors. In terms of , that's students.

On the other hand, of the students of the south campus are of music majors. That corresponds to students.

With a similar logic, the number of music students in the merged east campus will be .

The question implies that the sum of students in the two campuses should be equal to the number of music students in the east campus. That is:

.

Solve for :

.

In other words, there are students in the north campus and students in the south campus before the merger.

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.