A 2.5 ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles. The radius of the inner circle is ft. How much farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn?

15.71 ft

Step-by-step explanation:

Given that:

width of the circular track = 2.5ft

Suppose the radius of the inner circle is 57 ft since it is not given

Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft

The circumference of a circle = 2πr

For inner circle now, the circumference = 2 × π × 57 ft

For inner circle now, the circumference = 358.14 ft

For the outer circle, the circumference = 2 × π × 59.5 ft

For the outer circle, the circumference = 373.85 ft

The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn

∴

= ( 373.85 - 358.14 ) ft

= 15.71 ft

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

351.23

step-by-step explanation: