The following rational equation has denominators that contain variables. for this equation, A. write the value or values of the variable that makes the denominator zero. These are the restrictions on the variable. B. keeping the restrictions in mind, solve the equation.
3/x+4 + 2/x-4 = 16/(x+4)(x-4)
A. what is/ Are The value our values of the variable that make(s) the denominators zero?
x=

For the given rational equation, we have that:

The rational equation given in this problem is:

Then, applying the least common factor:

Item a:

The denominator cannot be zero, hence:

The values of the variable that make(s) the denominators zero are x = -4 and x = 4.

Item b:

However, x = 4 makes the denominator zero, hence the equation has no solution.

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A. -4 and 4

B. No solution.

Step-by-step explanation:

The given equation is

A.

Equate the denominators equal to 0 to find the restrictions on the variable.

Therefore, .

B.

We have,

Multiply both sides by (x-4)(x+4).

Add 4 on both sides.

Divide both sides by 5.

Here the solution is x=4 but it is the restricted value.

Therefore, the given equation has no solution.

-81 -56 -27 0 81

step-by-step explanation:

the answer is 18 units because there are 18 small cubes inside the rectangle

hope this and p.s i am also in k12

step-by-step explanation: