WILL GIVE BRAINLIEST! Prove that a quadrilateral ABCD with vertices A(–1, –2), B( 2, –5), C(1, –2), and D( –2, 1) is a parallelogram. Find the point of intersection of the diagonals of parallelogram ABCD. Provide your complete solutions and proofs in your paper homework and enter the numeric answers online.

Step-by-step explanation:

To prove a quadrilateral a parallelogram we prove,

1). Length of opposite sides are equal.

2). Slopes of the opposite sides are same.

Length of AB =

                      =

                      =

Length of BC =

                      =

Length of CD =

                      =

Length of AD =

                      =

Therefore, AB = CD and BC = AD (Opposite sides are equal in length)

Slope of AB =

                    =

                    = -1

Slope of BC =

                    = -3

Slope of CD =

                    = -1

Slope of AD =

                    = -3

Slope of AB = slope of CD and slope of BC = slope AD

Therefore, AB║CD and BC║AD

Hence ABCD is a parallelogram

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

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step-by-step explanation: