Point T is on line segment \overline{SU} SU . Given TU=4x+1,TU=4x+1, SU=8,SU=8, and ST=3x, ST=3x, determine the numerical length of \overline{TU}. TU .

Step-by-step explanation:

If point T is on the line SU, then ST+TU = SU. Given  TU=4x+1, SU=8, and ST=3x

Substituting the given values into the expression ST+TU = SU

8 = 3x+4x+1

8 = 7x+1

collect like terms;

7x = 8-1

7x = 7

Divide through by 7

7x/7 = 7/7

x = 1

Substitute x = 1 into the expression TU = 4x+1 to get the length of TU

TU = 4(1)+1

TU = 4+1

TU = 5

Hence the length of TU is 5

a

step-by-step explanation:

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13