X2 - 13x + 40 = 0 Hey, I got this on my math homework and I need help with figuring out how to solve it

x=8   x=5

Step-by-step explanation:

X^2 - 13x + 40 = 0

What two numbers multiply to 40 and add to -13

-8*-5 = 20

-8-5 = -13

( x-8) (x-5) =0

Using the zero product property

x-8=0    x-5 =0

x=8   x=5

To solve this polynomial equation, we will first factor the left side.

On the left, we have a special type of trinomial

that can be factored as the product of two binomials.

X² breaks down as x · x and we are looking for

the factors of 40 that add to the middle term, -13.

Since the middle term is negative, we use negative factors of 40.

The factors that work are -8 and -5.

So we have (x - 8)(x - 5) = 0.

If (x - 8)(x - 5) = 0, that means that either x - 8 = 0 or x - 5 = 0.

Solving for x in each equation, we have x = 8 or x = 5.

We can write this as the set of numbers {8, 5}.

add an image, and i will answer

step-by-step explanation:

there is no question content here, but you for the free points! : d