Find the equation of a line containing the point (8.3) and has a slope of 5. Write the equation in slope-intercept form

Step-by-step explanation:

So we want to find the equation of a line with a slope of 5 and passes through (8,3).

To do so, we can use the point-slope form. This point-slope form is:

Let's let (8,3) be x₁ and y₁ and let's let m equal 5. Therefore:

Distribute the right:

Add 3 to both sides:

That would be our equation in slope-intercept form.

And we're done!

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.