Find the equation of a Horizontal line containing the point (-1,3)

We want to find the equation of a horizontal line such that it passes through a given point.

The answer is: y = 3

We know that the general form of a horizontal line is:

y = a

Where a is a real number.

Now, we also want that our line passes through the point (-1, 3).

Notice that the y-value of the point is 3, and in a horizontal line we can have only one value of y, so the horizontal line must be:

y = 3

The graph of the line and the point can be seen below

If you want to learn more you can read:

link

y = 3

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

We know that a horizontal line has a slope of zero:

Slope m = 0

y = 0x + b

y = b

Since we are trying to find a line that fits with (-1, 3), we look solely at the y-value.

y = 3

its 4 because 2 times 2 is 4, if you double the number two you get four

9x