There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. Find the smallest integer in the sequence.

4

Step-by-step explanation:

Let the consecutive integers be x, x+1 and x+2.

There are three consecutive integers such that twice the sum of the smallest and the largest is eight more than twice the largest. This means that:

2(x + x+2) = 2(x+2) + 8

2(2x + 2) = 2x + 4 + 8

4x + 4 = 2x + 12

Collect like terms

4x - 2x = 12 - 4

2x = 8

x = 8/2

x = 4

The smallest integer in the sequence is 4

150.6

all i did was i multiplied 5.02 by 30

i think it would be c

mark brainliest if im right

step-by-step explanation: