Choose the number in which the digit 2 is ten times greater than the digit 2 in 426.

237

Step-by-step explanation:

Ok we can write 426 as:

400 + 20 + 6

Then the 2 in 426 is in the place of the tens and represents a 20.

If we want a number with a 2 that is 10 times greater than 20, we have that:

10*20 = 200.

Then we should find a number with a 2 in the hundreds place, an example can be:

237

where we can write this number as:

237 = 200 + 30 + 7

and the 2 is in the hundreds place.

my acc plz

step-by-step explanation:

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18