Please please help me

0.64

Step-by-step explanation:

so first get the area of the circle to get the probability of a point being in that circle (PS:don't use perimeter since a point can also be in the circle not only round it)

the area is 50.286

then get the area of the square which is 32 so I saw that in a total possible area a point can be of 50.286 ,32 of it will be in the square so to get the probability of a point in the square it will be the favourable area of 32 over the possible area of 50.286 then I divided to get 0.63636 then I rounded off to two decimal places

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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