In a poll of 555 randomly selected students, 40% stated that they enjoyed statisticsa. Identify the number of students who say that they enjoy statistics? Round to the nearest whole student if necessary. b. Construct a 95% confidence interval estimate of the percentage of all students who say that they enjoy statistics. c. Can we safely conclude that majority of students enjoy statistics? Explain.

a

b

c

No we  can not safely conclude that majority of students enjoy statistics because the upper limit of the confidence level is less than 50%

Step-by-step explanation:

From the question we are told that

   The  sample size is  

   The  percentage that enjoyed statistics is

Generally the number of student who say they enjoyed statistics is mathematically represented as

=>    

Given that the confidence  level  is  95%  then the  level of significance is mathematically represented as

=>    

The critical value  of   obtained from the normal distribution table  is  

 The  margin of error is mathematically represented as

=>          

=>.      

The 95% confidence interval is mathematically represented as

=>        

=>        

No we  can not safely conclude that majority of students enjoy statistics because the upper limit of the confidence level is less than 50%

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

ok so what's the question?

step-by-step explanation: