A triangle has a perimeter of 48 inches. Side B is nine inches longer than side A. The base is 7 inches more than twice side A. What are the dimensions of the triangle?

  (A, B, C) = (8, 17, 23) inches

Step-by-step explanation:

We can let A, B, and C represent the corresponding side lengths. Then we are given ...

  A + B + C = 48 . . . . . . the perimeter is 48 inches

  B = A + 9 . . . . . . . . . . . B is 9 inches longer than A

  C = 2A +7 . . . . . . . . . . the base (remaining side) is 7 inches more than ...

Substituting for B and C in the first equation, we have ...

  A + (A+9) +(2A+7) = 48

  4A = 32 . . . . . . . . . . . . . . collect terms, subtract 16

  A = 8

  B = A+9 = 17

  C = 2A +7 = 23

Side A is 8 inches, side B is 17 inches, and side C is 23 inches.

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

sorry man i accidentally pressed yes my bad

step-by-step explanation: