The length of a rectangle is one more than four times its width. If the perimeter of the rectangle is 62 meters, find the dimensions of the rectangle.

Length = 25 meters

Width = 6 meters

Step-by-step explanation:

62 = 2(a+b)

a = 4b + 1

a = length

b = width

then:

62 = 2((4b+1)+b)

62/2 = 4b+b+1

31 = 5b + 1

31 - 1 = 5b

30 = 5b

b = 30/5

b = 6m

a = 4b + 1

a = 4*6 + 1

a = 24 + 1

a = 25m

Check:

62 = 2(6+25)

62 = 2*31

110

step-by-step explanation:

based on the question i am guessing that it is a typo for abc

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder