EFGH is a rhombus. Rhombus E F G H is shown. Diagonals are drawn from point E to point G and from point F to point H. All sides are congruent. Given EG = 16 and FH = 12, what is the length of one side of the rhombus? 6 units 8 units 10 units 14 units

10 units

Step-by-step explanation:

The diagnonals of a rhombus meet at right angle to their selves and bisect each other.

So one quarter will form a right angle triangle of base 6 and height 8.

Let The length of one side of the rhombus be x

X²= 8²+6²

X²= 64+36

X²= 100

X= √100

X= 10 units

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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