An advocacy group claims that the mean braking distance of a certain type of tire is 75 feet when the car is going 40 miles per hour. In a test of 80 of these tires, the braking distance has a mean of 77 and a standard deviation of 5.9 feet. Find the standardized test statistic and the corresponding p-value.

The calculated value t = 3.032 >  1.9904 at 5% level of significance

Step-by-step explanation:

Step(i):-

Given mean of the population 'μ'=75 feet

Given mean of the sample(x⁻) = 77

Given standard deviation of the sample(S) = 5.9

Given sample size 'n' =80

Step(ii):-

Test statistic

            t = 3.032

Degrees of freedom ν=n-1 = 80-1 =79

tabulated value = 1.9904 at 5% level of significance

The calculated value t = 3.032

Final -

The calculated value t = 3.032 >  1.9904 at 5% level of significance

i used to know but i learned it a long time ago sorry

step-by-step explanation:

john earns $14.00 for two hours of work.