3y^2+y^- 5+ 4y+2y^3+8

9y+3

Step-by-step explanation:

you add all the common numbers and you end up with:

9y^6+3+y^-5

then you put the y^-5 under the other numbers and make it positive so it becomes:

9y^6+3/y^5, then you subtract the exponents of y: 6-5, so that cancels out the y on the bottom making it:

9y+3