In problems 1-3, show that each of the functions on the left is a 2-parameter family of solutions of the differential equation on its right. 1. y = c1 + c2e^-x + x^3/3, y" + y' - x^2 - 2x = 0.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

2

step-by-step explanation: