What is the solution of the system of linear equations? y = 3x - 2 y - 2 = x

x = 2 y = 4

Step-by-step explanation:

y = 3x - 2

x = y - 2

Plug in the equation of x into the first equation and solve for y.

y = 3x - 2

y = 3(y - 2) - 2 Multiply out

y = 3y - 6 - 2

y = 3y - 8     Add 8 to each side

y + 8 = 3y - 8 + 8      8 cancels on the right

y + 8 = 3y          Subtract y from each side

y - y + 8 = 3y - y       The y on the left cancels

8 = 2y      Divide each side by 2

8/2 = 2y/2   2 on the right cancels because 2/2 = 1

8/2 = y

4 = y  

Now plug your answer into the 2nd equation given to solve for x.

x = y - 2

x = 4 - 2

x = 2

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8