Order of operations A set of three scores consists of the values 6, 3, and 2. 1. Σ2X – 2 =.a. 35.b. 33.c. 22.d. 6.2. Σ(2X)² =.a. 248.b. 124.c. 61.d. 39.

The results of the order of operations are: and

The scores are given as:

x = 6, 3 and 2

This is represented as:

So, we have:

Evaluate the products

This is represented as:

So, we have:

Evaluate the products

Evaluate the squares

Hence, the results of the order of operations are:

and

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Step-by-step explanation:

Given the order of operations A set of three scores to consists of the values 6, 3, and 2, we are to evaluate the following

1) Σ2X – 2

= 2(6)+2(3)+2(2) – 2

= 12+6+4–2

= 22–2

= 20

2) Σ(2X)² = (2×6)²+(2×3)²+(2×2)²

Σ(2X)² = 12²+6²+4²

Σ(2X)² = 144+36+16

Σ(2X)² = 144+52

Σ(2X)² = 196