Three boys were running around the track. The first can run 1 lap in 15 min. The second can run 1 lap in 25 min. and the third can run a lap in 10 min. If the boys start running at 12:45, what time will all 3 boys pass each other again?

At 15:15

Step-by-step explanation:

Given,

the 1st boy can run a lap in 15 minutes

the 2nd boy can run a lap in 25 minutes

the 3rd boy can run a lap in 10 minutes

Now if they start running at 12:45,they will meet after the time which will be equal to the L.C.M. of their time need to run a lap.

of 15,25 & 10 = 150

So,they will pass each other after 150 minutes or 2 hours & 30 minutes.

If we add it with 12:45 we'll get 15:15 or 3:15 pm

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

idk

step-by-step explanation: