A map is created on the coordinate plan, lori's house is located at ( -3, 7) and Andreas house is located at (-3,-4). Each unit on the map represents 0.2 mile.

2.2 miles.

Step-by-step explanation:

I guess that we want to find the distance between Lori's and Andrea's houses.

First, we have the locations:

L = (-3, 7)

A = (-3. -4)

To find the distance (in units) between two coordinate points (a1, a2) and (b1 b2) we can use the formula:

Distance = I (a1, a2) - (b1, b2)I = √( (a1 - b1)^2 + (a2 - b2)^2)

Then in this case we have that:

Distance = √( ( -3 -(-3))^2 + (7 - (-4))^2) = √( 0 + 11^2) = 11

The distance between their houses is 11 units.

And we know that each unit represents 0.2 miles, then 11 units represent 11 times that amount, the distance in miles will be:

D = 11*0.2 miles = 2.2 miles.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.