Omar's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs $4.10 Omar per pound, and type B coffee costs $5.30 per pound. This month, Omar made 141 pounds of the blend, for a total cost of $640.50. How many pounds of type A coffee did he use?

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Let's use the variables A and B to represent the number of pounds used of types A and B.

4.10A+5.30B=640.50

A+B=141

Let's rearrange the bottom equation to solve for B.

A+B=141

Subtract A from both sides.

B=141-A

We can put this value of B into the first equation to solve for the number of pounds of type A Omar used.

4.10A+5.30(141-A)=640.5

We use distributive property to undo parentheses.

4.10A+747.3-5.3A=640.5

We combine like terms.

-1.2A+747.3=640.5

Subtract 747.3 from both sides.

-1.2A=-106.8

Divide both sides by -1.2

A=89

Omar used 89 pounds of type A coffee in this month's blend.

Have a wonderful day! :D

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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step-by-step explanation:

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.