In triangle $ABC,$ the angle bisector of $\angle BAC$ meets $\overline{BC}$ at $D,$ such that $AD = AB$. Line segment $\overline{AD}$ is extended to $E,$ such that $CD = CE$ and $\angle DBE = \angle BAD$. Show that triangle $ACE$ is isosceles.

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.

Y= a(x-3)squared-1 what is the value of a

The angle of depression from the top of the tree to the tip of the shadow is 25°. find the height of the tree to the nearest tenth. a. 16.8 feet b. 18.2 feet c. 23.4 feet d. 39.7 feet