Which statement completes step 5 of the proof? у
4
f
3
g
-2
K
L'
-4
-3
-2
-1
0
2
-1
J
-2
-3
-4
Step 1 KL is parallel to the y-axis, and JL is parallel to the x-axis.
Step 2 AJKL was rotated 90° clockwise to create AJ'KL'. Point K did not change position, so it remains point K. Therefore, AJKL - AJ KL.
Step 3 KL is perpendicular to the y-axis, and J'L' is perpendicular to the x-axis.
Step 4 JK lies on line f and has a slope of 3.
Step 5 ?
Step 6 The product of the slopes of JK and J'K is -1; therefore, lines f and g are perpendicular.
KL lies on line g and has a slope of
-
1
JK lies on line g and has a slope of