Mathematics, 04.09.2020 08:01 alphaaz23415
A projectile is launched from ground level with an initial velocity of
v 0
v0 feet per second. Neglecting air resistance, its height in feet t seconds after launch is given by
s equals negative 16 t squared plus v 0 t
s=−16t2+v0t. Find the time(s) that the projectile will (a) reach a height of
288
288 ft and (b) return to the ground when
v 0
v0
equals
=
144
144 feet per second.
Answers: 1
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A projectile is launched from ground level with an initial velocity of
v 0
v0 feet per second...
v0 feet per second...
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