A bus travels the 100 miles between A and B at 50 mi/h and then another 100 miles between B and C at 70 mi/h. The average speed of the bus for the entire 200-mile trip is:

Step-by-step explanation:

The average speed is defined as the total distance traveled divided by the total time taken.

from A to B

distance= 100 miles

speed= 50 mi/h

speed= distance/time

time= distance/speed

time= 100/50

time= 2 hours

from B to C

distance= 100 miles

speed= 70 mi/h

speed= distance/time

time= distance/speed

time= 100/70

time= 10/7 hours

Average speed= total distance/total time

total distance= 200 mile

total time= 2+10/7= (14+10)/7= 24/7

Average speed= 200/24/7

Average speed= 200*7/24

Average speed= 1400/24

Average speed= 58.3 mi/hour

a=r

d=q

c=p

b=s

hope this !

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°