PLEASE HELP ME I WILL MARK AS BRAINLIEST A map has a scale of
5 in. = 16 mi. If you measured the distance between two cities to
be 16 in. on the map, how many miles would it actually be?
If necessary, round your answer to the nearest tenth.

51.2 mi

Step-by-step explanation:

Proportions:

5 in ⇔ 16 mi

16 in ⇔ C mi

C = 16*16/5

C = 51.2 mi

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

6 meters

step-by-step explanation: