Write the equation of the line through (-2,1) that is parallel to y=-5x+27

The answer is

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is y = - 5x + 27

Comparing it with the general equation above

Slope = - 5

Since the lines are parallel their slope are also the same

Slope of parallel line = - 5

So the equation of the line using point

(-2,1) and slope - 5 is

y - 1 = - 5( x + 2)

y - 1 = - 5x - 10

y = - 5x - 10 + 1

We have the final answer as

Hope this helps you

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