You have three numbers. Two of the numbers are 24 and 42. What is the GCF of these two numbers? The third number is greater than 42 and does not change the GCF. What is one possibility for the third number?

GCD(24,42) = 42

48 is one possibility for the third number.

Step-by-step explanation:

Given two numbers out of 3 are 24 and 42.

Prime factorization of 24 and 42 is

24 = 2 x 2 x 2 x 3

42= 2 x 3 x 7

We can see the greatest common division (GCD) of 24 and 42 = 2 x 3 = 6

Now if third number is greater than 42 and does not change the GCF, the we take nearest possible number as 42 + GCD(24,42) = 42+6 = 48

Such that GCD (24,42,48)=6

So, 48 is one possibility for the third number.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752