Ralph has a new rectangular back yard. The area of the back yard is 32 feet. The Length of the rectangle is 2 times the Width. Find the perimeter of the rectangular back yard.

  24 feet

Step-by-step explanation:

Let w represent the width of the rectangle. Then its length is 2w, and its area is ...

  A = Lw

  32 = (2w)(w) = 2w^2 . . . fill in the given values

  16 = w^2 . . . . . . . . . . . . divide by 2

  4 = w . . . . . . . . . . . . . . take the square root

  8 = 2w = L . . . . . . . . . find the length

The dimensions of the yard are 8 feet long and 4 feet wide.

__

The perimeter is ...

  P = 2(L +w) = 2(8 +4) = 2(12) = 24 . . . . feet

The perimeter of the rectangular back yard is 24 feet.

answer is 67%

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet