A construction worker tosses a brick from a tall building. The brick's height (in meters above the ground) t tt seconds after being thrown is modeled by h ( t ) = − 5 t 2 + 20 t + 105 h(t)=−5t 2 +20t+105h, left parenthesis, t, right parenthesis, equals, minus, 5, t, squared, plus, 20, t, plus, 105 Suppose we want to know the height of the brick above the ground at its highest point. 1) Rewrite the function in a different form (factored or vertex) where the answer appears as a number in the equation. h ( t ) = h(t)=h, left parenthesis, t, right parenthesis, equals 2) At its highest point, how far above the ground was the brick?

Step-by-step explanation:

You have to put this into vertex form in order to find the time it was at its highest. To do this you have to complete the square. First rule is to set the equation equal to 0, then move the constant over to the other side of the equals sign. Let's do that:

The next rule is that the leading coefficient HAS to be a positive 1, and right now ours is a -5. So we have to factor out the -5, leaving us:

The next step is to take half the linear term, square it, and add it to both sides. Our linear term is a -4; half of that is -2, and squaring -2 gives you a 4. So adding in the 4 to the parenthesis on the left is a given; however, don't forget about the -5 hanging out in front as a multiplier. We didn't just add in a 4, we added in -5 times 4 which is -20. Putting all that together:

The reason we do this is apparent on the left side. We create a perfect square binomial of the form

Notice that I also added the 2 negatives on the right at the same time. Now the last step is to move the -135 back over with the other guys and set it equal to y again:

Now it's in the form

where (h, k) are the vertex, or the highest point of the parabola: (2, 135). This means that at 2 seconds the object was at its highest point in its path of 135 m.

answer: b.48 for

step-by-step explanation:

the first one, all those points on the line just make a strait line.