I NEED THIS BY TODAY PLS HELP ME, I NEED IT FULLY DONE PLEASE!!! A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F.

Part A: Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form. (2 points)

Part B: Describe the graph of the inequality completely from Part A. Use terms such as open/closed circles and shading directions. Explain what the solutions to the inequality represent. (4 points)

Part C: In January 1989, the temperature in Nome, Alaska dropped to −49° F. Would the gas in the driver's truck have remained in liquid form so he could have driven on this day? Why or why not? (4 points)

Part A

 -40 < x < 140

x is the temperature

As long as x is larger than -40, but also less than 140, then the fuel will remain as a liquid. Put another way: If x is between -40 and 140, excluding both endpoints, then the fuel stays as a liquid.

Part B

The graph will have open holes at -40 and 140, with shading in between. This is all on a number line.

This visually represents all possible values of x on a number line such that -40 < x < 140 as mentioned earlier. Anything in the shaded region works as a possible valid temperature. The open holes say to the reader "this endpoint is not included". So x = -40 is too cold because this is when the fuel freezes, which is why x = -40 is not included.

Random side note: -40 degrees C is equal to -40 degrees F. This is the only time when the two unit measures are the same.

Part C

No, the fuel would have frozen solid. The driver would not be able to operate the truck.

Draw out a number line. Plot -40 and -49. You'll see that -49 is to the left of -40. So -49 is a smaller number.

It might help to think of a thermometer. As the temperature goes down, so does the red stuff inside the thermometer, and it goes down a number line. Draw a vertical number line to have -49 below -40 to show that -49 is colder than -40. The lowest we can go is -40, so we're past that threshold when it comes to -49.

In short, -49 is colder than -40 so the fuel is unfortunately frozen over.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.