Find x in 9^2x+1=81^x-2 ÷3x

Step-by-step explanation:

9^(2x+1) = 81^(x-2)/ 3^x

or, 9^(2x+1)/ 9^2(x-2) = 1/3^x

or 9^( 2x+1+2x-2) = 1/3^x

or, 9^(4x-1) = 3^-x

or, 3^(8x-2) = 3^-x

or, 8x-2 = -x

or, 8x+x = 2

or, 9x = 2

or , x = 2/9

f

step-by-step explanation:

f

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: